a^2+54a=0

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Solution for a^2+54a=0 equation: 



a^2+54a=0

a = 1; b = 54; c = 0;
Δ = b2-4ac
Δ = 542-4·1·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-54}{2*1}=\frac{-108}{2}
=-54
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+54}{2*1}=\frac{0}{2}
=0
$

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